![If f (x) = cos [ pi ^ 2 ] x + cos [ - pi ^ 2 ] x where. [ . ] stands for the greatest integer function then which of the following is wrong.](https://haygot.s3.amazonaws.com/questions/1775744_1132743_ans_307c152a00c246d3901f18ffdd316646.jpeg "If f (x) = cos [ pi ^ 2 ] x + cos [ - pi ^ 2 ] x where. [ . ] stands for the greatest integer function then which of the following is wrong.")
If f (x) = cos [ pi ^ 2 ] x + cos [ - pi ^ 2 ] x where. [ . ] stands for the greatest integer function then which of the following is wrong.
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![If f(x)=cos[pi/x] cos(pi/2(x-1)) ; where [x] is the greatest integer function of x,then f(x) is continuous at :](https://d10lpgp6xz60nq.cloudfront.net/ss/web/51560.jpg "If f(x)=cos[pi/x] cos(pi/2(x-1)) ; where [x] is the greatest integer function of x,then f(x) is continuous at :")
If f(x)=cos[pi/x] cos(pi/2(x-1)) ; where [x] is the greatest integer function of x,then f(x) is continuous at :
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![functions - Maximum and minimum of $f(x)= \sin x(1- \cos x)$ at $[0,2\pi] \to [-2,2|$ - Mathematics Stack Exchange](https://i.stack.imgur.com/0fep8.png "functions - Maximum and minimum of $f(x)= \sin x(1- \cos x)$ at $[0,2\pi] \to [-2,2|$ - Mathematics Stack Exchange")
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![real analysis - Prove that, $\cos x\ge1-{2x\over\pi}\ \forall x\in[0,{\pi\over2}]$ - Mathematics Stack Exchange](https://i.stack.imgur.com/wunIp.png "real analysis - Prove that, $\cos x\ge1-{2x\over\pi}\ \forall x\in[0,{\pi\over2}]$ - Mathematics Stack Exchange")
real analysis - Prove that, $\cos x\ge1-{2x\over\pi}\ \forall x\in[0,{\pi\over2}]$ - Mathematics Stack Exchange
Szinusz- és koszinusz függvények | Baamboozle - Baamboozle | The Most Fun Classroom Games!
